00:01
Dear students, here we have to convert vaniline to vanilla alcohol using sodium borohydrate in the presence of sodium hydroxide.
00:09
So in the presence of sodium hydroxide alkyly, we have to give the mechanism here.
00:14
So here because alkalis is present, therefore this vaniline will lose this first hydrogen.
00:20
So we'll get, let us start from this, we'll get deprotonated vaniline.
00:30
So here we'll get o minus, then other portions as it is coh.
00:40
Then sodium borohydide, from sodium borohydrideide, n -a -b -h4, it will dissociate into na -b -h -4 minus.
00:50
So one hydride transfer will take place.
00:56
So this hydride will attack to this carbon and the bond will polarize, pi bond will polarize like this, pi electrons towards oxygen...