00:01
Hello students, this is the equation given in the question.
00:03
That is, sodium carbonate will react with silver nitrate to give sodium nitrate and silver carbonate.
00:10
So, we have to write the balance equation for this reaction.
00:14
First of all we have to find out the molecular formula for this compound.
00:18
The sodium will exist in the plus 1 charge and the carbonate will exist in the minus 2 charge.
00:24
On crisscrossing this we will get the formula of na2co3.
00:29
This will react with silver nitrate.
00:31
Silver will exist in plus 1 charge and the nitrate will have the minus 1 charge.
00:36
So, this will be agno3 will give us sodium in the plus 1 charge and the nitrate in minus 1 charge.
00:47
On crisscrossing this we will get nano3 plus ag plus in the plus 1 charge and the carbonate in the minus 2 charge.
00:57
On crisscrossing this we will get ag2co3.
01:00
Now we are going to balance this.
01:02
Let us start with counting the sodium atom...