00:01
Right, the balanced neutralization reaction.
00:04
So you have the sulfuric acids, we react with k -o -h.
00:13
Sophobic acid has two protons, and k -o -h only have one oh group.
00:19
So one sulfuric acid will react with two mores of the k -o -h potassium hydroxide.
00:25
To form two mores of water and one more of the potassium sulfate.
00:36
So it says, initially you have 0 .95 liters of the point finite morph of the sulfuric acid.
00:48
It react with 0 .9 liters of the 0 .27 mores of k -oh.
00:55
Which one is excessive, right? so first we can calculate the mores of the sulfuric acid.
01:05
We call that initially before the neutralization.
01:08
So 0 equals to concentration times volume.
01:13
So it's 0 .95 times 0 .49.
01:27
It's about 0 .465 more.
01:33
And we can calculate the k -oh that is added.
01:42
Same equals to c times v...