Write the equation for the reaction of p-tertbutylphenol...

Name: Write the equation for the reaction of p-tertbutylphenol with NaOH (sodium hydroxide). Include the structure for the product(s). Also, include the pKa for p-tertbutylphenol and the pKa for the acid product. For this chemical reaction, indicate if reactants or products are favored. Save your answer as a pdf or jpg and submit your answer as a file upload in this question.
Uploaded: 2022-11-23T07:35:59-08:00
Duration: 6 min 2 s
Channel: Adi S
Description: Write the equation for the reaction of p-tertbutylphenol with NaOH (sodium hydroxide). Include the structure for the product(s). Also, include the pKa for p-tertbutylphenol and the pKa for the acid product. For this chemical reaction, indicate if reactants or products are favored. Save your answer as a pdf or jpg and submit your answer as a file upload in this question.

Write the equation for the reaction of p-tertbutylphenol with NaOH (sodium hydroxide). Include the structure for the product(s). Also, include the pKa for p-tertbutylphenol and the pKa for the acid product. For this chemical reaction, indicate if reactants or products are favored. Save your answer as a pdf or jpg and submit your answer as a file upload in this question.

Transcript

00:01 The value of pca of acid and base is about 10.

00:13 Then only the forward reaction, forward reaction, favor.

00:27 In the first reaction, the given compound is here is double one o, double one o, when it reacts with sodium hydroly oxide, n -a -o -h, what happens? this bond will shift to this oxygen and this oxygen having lone paraphalacton and this lone parapherlachron will attract those hydrogen atoms.

00:52 So the product will be formed as double bond, double bond, o negative plus h -o -h and here o negative with sodium positive.

01:08 Here water is having pca value 15 .7 and this compound is having pca 4 .52.

01:22 If we will calculate the difference of the pca values, it will be 15 .7 minus 4 .52 and its value will be 11 .18.

01:36 And 8 due to this value which is higher than 10 so the reaction will be favored.

01:46 Another reaction is given as h -c triple bond p -c -c -h -c -h.

01:54 When it reacts with n -a -o -h, what happened the bond will shift to these carbon atoms and these o -h group will attack this hydrogen atom.

02:08 Though our product will be formed as na plus c negative triple 1c 1ch3 with another product water h oh.

02:23 If you will see the pca value is 25 and here pcaa is 15 .7.

02:36 So the difference will be difference is 15.

02:44 0 .7 minus 25 is equals to minus 9 .3 and this reaction will not favor.

03:01 In the next reaction we will see the compound h .2 and cyclohexen group when it is react with fc.

03:14 But, of it, the nitrogen here is having lone -pylochron and this lone -pypropyloktron will attack this hydrogen atom and the board will go to this chlorine atom.

03:26 The product will be formed as nh3 positive plus cl negative.

03:35 Here the pca value of this compound is 10 .66 and here it is having minus 8 .0 is the pk value...

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