00:01
We want a particular sign function that has an amplitude is equal to 2, and it's a period equal to 3 pi.
00:16
And lastly, that it's phase shift is equal to negative pi over 3.
00:23
Okay, so in order to do this, the first thing to keep in mind is that, well, amplitude is our a value, period is going to help us to find our b value, and our phase shift is going to be our c value.
00:36
So, and that follows from the sinusoidal function of a sine of b parentheses x, and then minus whatever the c value is.
00:52
This is a plus d component, which is the vertical shift or the midline, but we don't have that here.
00:57
So we're going to ignore that.
00:59
So in this part here, so let's go ahead and find out what our b value is.
01:04
So then period is equal to 3 pi, so then that means our equation is going to be.
01:09
So it's period equals 2 pi over b, which means that the period is equal to 3 pi.
01:18
So then bringing the b over, we've got 3b times pi equals 2 pi...