00:02
Here in this problem, this reaction is given to nitric oxide plus bromine produces two nitrosil bromine.
00:13
And initial concentration of nitric oxide given 1 .20 molar and for bromine it is 0 .80 molar.
00:22
Now equilibrium concentration of nitrocyl bromide is 1 .00 molar.
00:28
We have to find out the value for casein.
00:33
Now let's write the equation again 2 no plus br2 producing 2 no br2 producing 2 no br nitrosyl bromide.
00:50
Now initial concentration of no is 1 .20 molar.
00:58
For bromine it is 0 .80 molar and initially the concentration is none here.
01:11
Now change concentration for this one say minus x so it will be minus x by 2.
01:18
Here 2 moles say no reacts with 1 mole of bromine.
01:24
So we are writing for change concentration for no minus x and here it will be minus x by 2 and here it is plus x.
01:38
So equilibrium concentration 1 .20 minus x, here 0 .80 minus x by 2, and here it will be x.
01:51
Now we'll write expression for kc...