Write the Henderson-Hasselbalch equation for propanoic acid solution (CH3CH2COOH, pKa 4.874). log Answer Dank quotient [A-VIHA] at three different pH values: Using the equation to calculate the = pH = 4.199
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It is CH3CH2COOH. Now, let's write the dissociation reaction for propanoic acid: CH3CH2COOH (aq) ↔ CH3CH2COO- (aq) + H+ (aq) The Henderson-Hasselbalch equation is given by: pH = pKa + log ([A-]/[HA]) For propanoic acid, pKa = 4.874, [A-] represents the Show more…
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Write the Henderson–Hasselbalch equation for a solution of propanoic acid (CH3CH2CO2H, pKa = 4.874) using HA, A−, and the given pKa value in the expression. pH = 4.874 + log ([A-]/[HA]) Using this equation, calculate the quotient ([A-]/[HA]) at pH 4.25, pH 4.874, and pH 5.50. [A-]/[HA] at pH 4.25: 0.2376 [A-]/[HA] at pH 4.874: 1 [A-]/[HA] at pH 5.50: 4.2266
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Write the Henderson-Hasselbalch equation for a propanoic acid solution (CH3CH2CO2H, pKa=4.874). Using the equation to calculate the quotient [A-]/[HA] at three different pH values. pH=4.568 [A-]/[HA]= pH=4.874 [A-]/[HA]= pH=5.366 [A-]/[HA]=
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