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This is the answer to chapter 21, problem number three from the smith organic chemistry textbook.
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In this problem, we're given three aldehydes, and we're asked to come up with the iupac name for each aldehyde.
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And so the first thing that i would do here is a is given as a lettering structure.
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I would rewrite that as a skeletal structure.
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It makes it much easier to see.
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And then we need to keep in mind our rules for naming.
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So a and b are open chain aldehydes and c is a ring.
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So the rules are going to be a little different.
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So for a and b, for the open chains, we need to find the longest chain that contains the alvehyde and name the molecule as a derivative of that.
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So for example, for a, we can number this.
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As well so we'll make the carbon with the aldehyde carbon number one so then we have two, three, four, and five.
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And so when we number it that way, it's a pentane derivative, so it's going to be pent an al.
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Because remember, we changed the ending to al to signify that it's an aldehyde.
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And then it looks like we have two sets of two methyl groups each on carbons three and four.
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And so altogether this becomes three, three, four, four tetramethyl pent -enow.
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Okay.
02:00
All right.
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So then moving on to b.
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So moving on to b, we'll do the exact same thing.
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So we need to determine the longest chain here and name the molecule as a derivative of that longest chain.
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And just change the ending to al to signify that it's an albohed...