00:01
This problem is asking us to provide iupac names for these six compounds shown here.
00:06
So if we start with compound a, we've got two benzene rings and two carbonyl groups connected by an oxygen.
00:15
So this piece tells us this compound is in hydride.
00:20
Now if we were to split this in half and pretend there's an h here, this would be a carboxylic acid.
00:27
It would be benzolic acid because of the benzene ring.
00:29
So together, since they're the same on both sides, it's just benzoic and hydride.
00:43
All right.
00:44
Next up, we have an ester, and we know this is an ester because we have a carbonyl group and an oxygen.
00:51
So with an astor, we're going to pay attention to two things.
00:54
Number one is the group sticking off the o.
00:57
This is going to be its own word out in front of the name, so in this case it's methyl.
01:03
And then we pay attention to our carbon chain.
01:06
So here we have a 10 carbon chain, so that is decane, and then the ending for an ester is 08.
01:14
So methyl dechanoate.
01:18
Next, this one looks pretty similar in structure to the previous one, because we have this carbonyl group.
01:23
But instead of an o, we have an n right here, which makes this an amid.
01:28
So again, we're going to look at this group and our chain.
01:32
This piece right here is another methyl, but this time because it's on an n, we have to indicate that.
01:37
It's n -methyl, and then now we have a six -carbon chain...