00:01
In this problem, we have been given the circuit and we have to write kvial equations considering three loops in this circuit and we have to get it in terms of i1, i2, i3, i4, and i s that's flowing through this.
00:20
So we have to just get the equation and we have to select three loops to get three equations.
00:26
So let's say we select, let's first name it ab, c, d, let's name this points as ef, g, and h.
00:37
So first we consider the loop ab, g, h, and in this loop we apply kirchav's voltage law, and according to that, the sum of voltage in a loop is zero.
00:49
So we move in this anti -clockwise manner, and let's say we start at this point, and let's take the potential as zero volt here.
00:56
So the same will be the potential here, but here the potential is 200 volt because there is a potential rise here because we have a source and the potential here that will be decreased because we are moving in the direction of current across a resistor.
01:14
And to determine the potential drop, we use omsla, according to which the potential difference is i times r.
01:21
So potential at point g, that will be 200 minus.
01:27
47 times i2, and same will be the potential at this point h, but the potential at point a, that will be increased by i1 times 27, because we are moving in the opposite direction of current.
01:41
So there will be potential gain here.
01:43
So we add 27 times i1, and this should be equal to 0.
01:48
So that's the first equation that we get, considering this loop abgha.
01:53
And next we consider the other loop b, c, fgb and let's move in anti -clockwise manner as well and let's consider now the point b with zero potential.
02:09
So potential at point c that will be zero as well...