\frac{1}{3} \ln(y^2 + 3) - \frac{1}{3} \ln(y + 3) =
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(1/3)ln(y^2 + 3) - (1/3)ln(y + 3) = ln((y^2 + 3)^(1/3)) - ln((y + 3)^(1/3)) Show more…
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