00:01
For this question, we have a reaction between lead -2 nitrate and calcium bromine, both of which are in solution, and we want the complete molecular reaction for this, the complete ionic equation, the net -ionic equation, and the reaction type.
00:15
So i already have our formulas for our two reactants.
00:19
So we have lead -2 nitrate, p -b -n -o -3, 2, and then we have calcium bromide, c -a -b -r -2.
00:27
Both of these are aqueous.
00:29
To determine our products, we have to know what type of reaction this is.
00:33
So this is going to be a double replacement reaction.
00:42
And so what happens in these types of reactions is everyone just switches partners, essentially.
00:48
So our calcium will go with nitrate, and then our lead will go with bromine.
00:53
So we'll get pbbr2, which is going to be a precipitate.
00:58
You have to use your solubility rules to determine if that's going to be soluble or not.
01:03
Because this is lead with a halide, it's going to be insoluble, and so we're going to say it's a solid.
01:10
And then we'll have calcium nitrate, which is c -a -n -3 -2.
01:16
And that'll be aqueous because nitrate is always aqueous.
01:20
Then we need to balance.
01:22
In this case, this reaction is already balanced, so we don't need to do anything, but that would be our last step if we needed to do that...