00:01
Hello students, hope you are doing great.
00:03
In this question, we are given that a terminal alkyne reacts with alkyl bromide in presence of a strong base that is sodium azide and it forms a product.
00:23
We have to find out what type of product is formed here and we have to write the iupac name of the product.
00:28
Let's start with the reactant.
00:30
So, here we have ch3, ch2, ch2, c triple bond c.
00:39
This reacts with sodium azide which is a strong base and this is a sp hybridized carbon and sp hybridized carbon is bonded with the proton that is acidic proton.
00:49
So, this base takes a acidic proton and that is the formation of an anion.
00:54
So, the anion that is formed here is this.
00:59
This anion formed in the first step reacts with alkyl halide...