00:01
Hello students, hope you are doing great.
00:03
In this question we are asked to find out the major product of the given organic reactions.
00:09
The first reaction we are given here is the propanoyl chloride reacts with sodium propanoate.
00:14
So here we have propanoyl chloride reacts with sodium propanoate.
00:27
So this negatively charged oxygen attacks on the carbonyl carbon, the pi electrons move to oxygen which revert back and this cl - is, cl - leaves as a giving group.
00:41
So the final product that we have here is like this.
00:45
This is an anhydride.
00:51
Next reaction we will see here is reaction between acetic anhydride reacts with 2 -pentanol.
01:08
So here we have 2 -pentanol in the first step which reacts with base in the first step and this oh - from the base takes proton from the oh group of the alcohol and there is negative charge on oxygen o-.
01:38
This then reacts with acetic anhydride.
01:42
Here we have acetic anhydride.
01:47
This reacts, this attacks on the carbonyl carbon, pi electrons move to oxygen, this reverts back and this group leaves from here and there is a formation of group like final product like this.
02:00
Here we have oxygen and this is the final product.
02:11
Next reaction is between ethyl acetate plus ethylamine.
02:22
So here we have ethyl acetate, here we have ch3 double bond o - and c2h5 which reacts with ethylamine.
02:38
C2h5 nh2.
02:41
Now this lone pair of nitrogen will attack on the carbonyl carbon, pi electrons will move to oxygen which will revert back and this o - will leave from here and there is formation of an amide here...