00:01
So we have given structures here first of all let me draw the structure first so we have a point line formula here so this is the structure we have okay now here here we have this one this one this one this one this one and this one all these are carbon atoms okay and in fact this is also a carbon atom okay in bond line structure we do not show carbon or hydrogen atom but we show the special functional group if present okay so now here this is the first carbon second carbon third carbon fourth carbon and fifth carbon so according to the iupac name systematic iapac name so we should select the longest carbon chain possible and if we have functional group so we should give the priority to the carbon atoms which are attest to the functional group that carbon should be given the least position possible so here i have oh h group on two carbon atoms so i am just counting the carbon atoms so that this oh h group containing carbon atom will get the lowest position so now on third carbon we have this double bonded oxygen so this is this represents the ketonic functional group and again on fourth carbon we have oh group the alcoholic group okay so now the systematic name will be two methyl so we have a methyl group substituted here okay this is here methyl group here we have to this carbon atom we have three hydrogen atoms attempt okay so this will be a methyl group here okay now we have this five carbon atom chain so that's why the prefix for the main carbon atom will be panned and now we have two kind of functional group here ketonic functional group and the alcoholic functional group so the main functional group here is ketone and this oh h group that is the alcoholic group so this will be treated as a secondary functional group.
02:42
This ketonic group is the primary functional group.
02:46
Now that's why we will use the prefixes to represent this secondary functional group and now to write the systematic name, we should consider the alphabetic order.
03:02
So this means that first of all we will represent hydroxy group.
03:08
So hydroxy is the prefix used for this alcoholic functional group when it is created as secondary functional group.
03:17
So we will write one for dihydroxy.
03:29
Now we have here this methyl group.
03:34
So this will be written as two methyl.
03:40
Now we have this.
03:42
Now we have this.
03:42
We will write total of 5 carbon atoms prefix will be pent and on third carbon atom we have this ketonic functional group so 3 pentanone so own is the suffix for ketone so that will be written okay so this is the systematic name now similarly we have next compound and it is to be noted that when substituents are repeated more than one time so we use prefixes in this case also here the oh h group is being repeated for two times so that's why di prefixes used here okay and then alphabetically since h comes first and then m so that's why we have written dihydroxy here and then methyl okay so now the next structure is oh h group then again this is a bond line formula and we have substituted attached here and we have double wanted oxygen atom now so we will select the longest carbon chain possible and the counting should be such like that the functional group attached to the carbon atom should be given the least position possible so here here here here and here so all these are carbon atoms and now counting the carbon atoms so, this will be here 1, 2, 3, 4, 5.
05:29
So there are 5 carbon atoms.
05:31
On 3rd carbon atom we have this double bonded oxygen atom.
05:35
So this is ketone here and we have hydroxy group that is the secondary functional group alcohol again because priority will be given to this ketone.
05:46
So now we have again this methyl substitute attempt here.
05:52
So this will be 5 hydroxy.
06:00
Then we have 2 methyl.
06:10
Then we have here on third carbon atom, ketonic group, so 3 pentanone again...
