Question

Write the two dimensional delta function for the circular polar coordinates $\vec{r}$, using $\vec{r}_0 = (\rho_0, \phi_0)$. \\ $\delta^{(2)}(\vec{r} - \vec{r}_0) = $ \\ Note: \\ When entering a Greek letter in the blanks above, you can either type the name of the letter (e.g. 'phi' for $\phi$), or find the letter in the Greek section of the calcpad. Be sure you are using lower case. \\ To enter $\delta(x)$, you can use the Greek pad or you can type 'delta'. Make sure you enclose the argument of the delta function in parentheses!

          Write the two dimensional delta function for the circular polar coordinates $\vec{r}$, using $\vec{r}_0 = (\rho_0, \phi_0)$. \\
$\delta^{(2)}(\vec{r} - \vec{r}_0) = $ \\
Note: \\
When entering a Greek letter in the blanks above, you can either type the name of the letter (e.g. 'phi' for $\phi$), or find the letter in the Greek section of the calcpad. Be sure you are using lower case. \\
To enter $\delta(x)$, you can use the Greek pad or you can type 'delta'. Make sure you enclose the argument of the delta function in parentheses!
        
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Write the two dimensional delta function for the circular polar coordinates r⃗, using r⃗0 = (ρ0, ϕ0). 

δ^(2)(r⃗ - r⃗0) = 

Note: 

When entering a Greek letter in the blanks above, you can either type the name of the letter (e.g. 'phi' for ϕ), or find the letter in the Greek section of the calcpad. Be sure you are using lower case. 

To enter δ(x), you can use the Greek pad or you can type 'delta'. Make sure you enclose the argument of the delta function in parentheses!

Added by Kevin C.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Write the two-dimensional delta function for the circular polar coordinates ho ,phi , using vec(r)_(0)=( ho _(0),phi _(0)). delta ^((2))((vec(r))-vec(r)_(0))= 5(2) (F -To)= Note: When entering a Greek letter in the blanks above, you can either type the name of the letter e.g. phi for φ or find the letter in the Greek section of the calcpad. Be sure you are using k.
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Transcript

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00:01 So we have a cylindrical coordinate such that rho and phi so we have r0 is equal to rho0 and phi0 so we have to find delta square for r minus r0 so that will be equal to h rho h phi delta rho minus rho0 delta phi phi0 now the h rho will be now when we change h rho here it means that if we change rho plus t rho rho 2 rho plus t rho so this is let's say this is…
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