00:01
Let us first draw the free body diagram of the frame support.
00:03
So f, b, d, we will first draw the free body diagram.
00:08
So the free body diagram will be like this.
00:13
It will be like this.
00:18
The vertically there will be a y force, and virginally there will be ax force.
00:23
And the force fbc will act in this direction.
00:28
This is fbc.
00:30
And the force p will act at this at a distance of 2 meter from lower end.
00:35
So this is force p.
00:38
This is force p and this is force f dc and angle theta this point is b this point is a this is a y this is a x this is 2 meter and this is 1 meter one meter now now we will calculate the theta theta will be equals to 10 inverse 10 inverse 4 divided by 3 it will come out to be 53 .1 degree.
01:13
Now let's write moment equation let's equate all moment about point a.
01:19
So it should be 0.
01:20
So p multiplied with 2 minus f bc sine 53 .1 degree is equal to multiplied by 3 is equal to 0.
01:36
So from this we get f bc xc is equal to 0 f bc is equal to 0 .8 -8 -3 p .0 .0 .0.
01:52
Let this equation be equation number 1.
01:55
Now, let us find the moment of inertia about x -axis.
02:02
So it will be, it will be dd cube divided by 12.
02:07
So here b is given as 0 .025 and d is given as 0 .035 cube divided by 12.
02:17
So, moment of inertia about x -axis is equal to 8 .9323 multiplied by 10 to the power of minus 8 meter to the power of 4...