Question

X-rays with an energy of 0.6 MeV undergo Compton scattering from a target. If the scattered x-rays are detected at 40 degrees relative to the incident rays, a. What are the x-rays and off what are they scattering? b. What is the wavelength of the incoming x-rays? c. How was the Compton scattering formula you will use for part (d) derived? d. What is the wavelength of the scattered x-rays?

          X-rays with an energy of 0.6 MeV undergo Compton scattering from a target. If the scattered x-rays are detected at 40 degrees relative to the incident rays,
a. What are the x-rays and off what are they scattering?
b. What is the wavelength of the incoming x-rays?
c. How was the Compton scattering formula you will use for part (d) derived?
d. What is the wavelength of the scattered x-rays?
        
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Added by Curtis S.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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X-rays with an energy of 0.6 MeV undergo Compton scattering from a target. If the scattered x-rays are detected at 40 degrees relative to the incident rays, a. What are the x-rays and off what are they scattering? b. What is the wavelength of the incoming x-rays? c. How was the Compton scattering formula you will use for part (d) derived? d. What is the wavelength of the scattered x-rays?
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Transcript

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00:01 So from the compton shift equation, let me write it down.
00:05 From compton shift equation, let me write down the formula.
00:17 Lambda dash minus lambda equals h by mec into 1 minus cost theta.
00:26 So rearranging this equation, del lambda equals h by mec.
00:35 Into 1 minus cos theta so we know the values now we are going to substitute this equals 6 .63 into 10 to the power minus 34 whole divided by 9 .11 into 10 to the power minus 31 into 3 into 10 to the power 8 into 1 minus cos 40 so while solving this we get the answer for del lambda as 5 0 .68 into 10 to the power minus 13 meter.
01:10 So the wavelength of the incoming photon.
01:24 So we know the formula lambda 0 equals hc by e0...
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