X-rays with wavelength 1.54 Å are “reflected” from the (110)...

X-rays with wavelength 1.54 Å are “reflected” from the (110) planes of a cubic crystal with unit cell a = 6 Å. Calculate the Bragg angle, ?, for orders of reflection, n = 1-5 For cubic system 1/d² = (h² + k² + l²) / a² 1/d² = (1+1+0) / a2 d= a/?2 = 6/1.414 = 4.243 n? = 2d sin? For n=1 1.54 Å=2*4.243(Å) sin ? 0.1815=sin ? ?=10.5

Transcript

00:01 In this question we are assigned with the task to calculate bragg angle theta for crystals with a unit cell length a of 6 am strong.

00:23 The wavelength of the x -rays used is given in the question as 1 .54 am strong and the planes of the cubic crystal is 1110.

00:36 This is the hkl notation for the plane in cubic crystals.

00:40 Hence in order to figure out brac angle theta we use the brac's equation brac equation is n lambda lambda is the wavelength of the x -rays used is equal to 2d sine theta b is the path length difference and theta is the instant angle or reflection angle of the x -rays on the given crystal planes.

01:11 N is the order of reflection.

01:14 Our task in this question is to calculate brax angle theta for different orders of reflection, that is for n 1 to 5.

01:29 First task is to calculate d, that is path length, this can be calculated from unit cell length a and the h scale notation for the plane by using this formula, that is, 1d, square is equal to hutskoya plus k square plus l square divided by k square by substituting all known data and simplifying we find the value of d as the value of d is 4 .243 this value is substituted in the brags equation and for order of reflection 1 the brags angle theta is calculated sign theta has taken on the left since it is the unknown.

02:22 By calculating, we find the value of sine theta as 0 .1815.

02:29 Hence, theta is 10 .457.

02:37 This is prax angle theta for order of reflection n is equal to 1...

Question

Please give Ace some feedback