Question

x\textsuperscript{2}-2x-8 Let $f(x) = \frac{x\textsuperscript{2}-2x-8}{x\textsuperscript{2}-x-6}$ Find: 1) Domain (in interval notation) (-2,3) 2) y-intercept(s) at the point(s) $(0, \frac{4}{3})$ 3) x-intercept(s) at the point(s) (4,0) 4) x-value of any holes 5) Vertical asymptotes at x = 3 6) Horizontal asymptote at y = 1 7) Oblique or slant asymptote at y = Write \"DNE\" if there is no answer.

          x\textsuperscript{2}-2x-8
Let $f(x) = \frac{x\textsuperscript{2}-2x-8}{x\textsuperscript{2}-x-6}$
Find:
1) Domain (in interval notation) (-2,3)
2) y-intercept(s) at the point(s) $(0, \frac{4}{3})$
3) x-intercept(s) at the point(s) (4,0)
4) x-value of any holes
5) Vertical asymptotes at x = 3
6) Horizontal asymptote at y = 1
7) Oblique or slant asymptote at y =
Write \"DNE\" if there is no answer.

x2-2x-8
Let f(x) = (x2-2x-8)/(x2-x-6)
Find:
1) Domain (in interval notation) (-2,3)
2) y-intercept(s) at the point(s) (0, (4)/(3))
3) x-intercept(s) at the point(s) (4,0)
4) x-value of any holes
5) Vertical asymptotes at x = 3
6) Horizontal asymptote at y = 1
7) Oblique or slant asymptote at y =
Write D̈NEïf there is no answer.

Added by Justin S.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Carson Merrill

09/11/2023

Step 1

In this case, there are no restrictions on the values of x, so the domain is all real numbers. Therefore, the domain is (-∞, ∞). Show more…

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x2 - 2x - 8 Let f(x)= x2-x-6 Find: 1 Domain (in interval notation) (2,3) 2) y-intercept(s) at the point(s) (0,3) 3) x-intercept(s) at the point(s) (4,0) 4) x-value of any holes 5) Vertical asymptotes at x = 3 6) Horizontal asymptote at y = 7) Oblique or slant asymptote at y = Write "DNE" if there is no answer.