Question

\( x^{2}+y^{2}-8 x+2 y+8=0 \) is the equation of a circle with center \( (h, k) \) and radius \( r \) for: \[ h= \] \( \square \) and \[ k= \] \( \square \) and \[ r=\square \] Graph the circle. Clear All Draw: \( \square \)

          \( x^{2}+y^{2}-8 x+2 y+8=0 \) is the equation of a circle with center \( (h, k) \) and radius \( r \) for:
\[
h=
\]
\( \square \)
and
\[
k=
\]
\( \square \)
and
\[
r=\square
\]

Graph the circle.
Clear All
Draw:
\( \square \)

x^2+y^2-8 x+2 y+8=0 is the equation of a circle with center (h, k) and radius r for:

h=

□
and

k=

□
and

r=□

Graph the circle.
Clear All
Draw:
□

Added by Gregg M.

Beginning and Intermediate Algebra

Sherri Messersmith 2nd Edition

Chapter 14

Instant Answer

Solved by Expert Manuel Vasquez

Step 1

Step 1: Rewrite the given equation of the circle: \( x^2 + y^2 - 8x + 2y + 8 = 0 \). Show more…

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\( x^{2}+y^{2}-8 x+2 y+8=0 \) is the equation of a circle with center \( (h, k) \) and radius \( r \) for: \[ h= \] \( \square \) and \[ k= \] \( \square \) and \[ r=\square \] Graph the circle. Clear All Draw: \( \square \)