Question

$X_C = 31.8 \Omega$ $V_S = 10 V_{rms}$ $X_L = 62.8 \Omega$ $R = 56 \Omega$ Figure 17-6 For the circuit in Figure 17-6, the circuit impedance is A) $64.0 \Omega \angle 29.0^\circ$ B) $27.1 \Omega \angle 61.0^\circ$ C) $110 \Omega \angle 59.4^\circ$ D) $42.3 \Omega \angle -41.0^\circ$

Name: xc 318 omega vs 10 vrms xl 628 omega r 56 omega figure 17 6 for the circuit in figure 17 6 the circuit impedance is a 640 omega angle 290circ b 271 omega angle 610circ c 110 omega angle 46585
Uploaded: 2021-07-31T11:32:13-08:00
Duration: 5 min 48 s
Channel: Paul Ridder
Description: xc 318 omega vs 10 vrms xl 628 omega r 56 omega figure 17 6 for the circuit in figure 17 6 the circuit impedance is a 640 omega angle 290circ b 271 omega angle 610circ c 110 omega angle 46585

          $X_C = 31.8 \Omega$
$V_S = 10 V_{rms}$
$X_L = 62.8 \Omega$
$R = 56 \Omega$
Figure 17-6
For the circuit in Figure 17-6, the circuit impedance is
A) $64.0 \Omega \angle 29.0^\circ$
B) $27.1 \Omega \angle 61.0^\circ$
C) $110 \Omega \angle 59.4^\circ$
D) $42.3 \Omega \angle -41.0^\circ$

xc 318 omega vs 10 vrms xl 628 omega r 56 omega figure 17 6 for the circuit in figure 17 6 the circuit impedance is a 640 omega angle 290circ b 271 omega angle 610circ c 110 omega angle 46585

Added by James S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Paul Ridder

07/31/2021

Step 1

In this case, $R = 56 \Omega$, $X_L = 62.8 \Omega$, and $X_C = 31.8 \Omega$. So, $Z = 56 + j(62.8 - 31.8) = 56 + j(31)$. Show more…

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Thanks for your feedback!

$X_C = 31.8 \Omega$ $V_S = 10 V_{rms}$ $X_L = 62.8 \Omega$ $R = 56 \Omega$ Figure 17-6 For the circuit in Figure 17-6, the circuit impedance is A) $64.0 \Omega \angle 29.0^\circ$ B) $27.1 \Omega \angle 61.0^\circ$ C) $110 \Omega \angle 59.4^\circ$ D) $42.3 \Omega \angle -41.0^\circ$