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In this video, we're going to go through the answer to question number 21 from chapter 7 .5, where we're asked to find the solution in the last space of the following initial value problem.
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Okay, so taking blass transforms of both sides, we're using the fact that lepath transforms are linear to do it turn by term, and then using the standard formula for lepath transforms of derivatives.
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So y, capital y is the lv flash transformer of littal y.
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So then we're using the initial values to find the fast transform of the second derivative of y.
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Then we can do the same for the first derivative of y.
00:57
Okay, cos t minus sine t.
01:01
So cos t is going to be s over s minus one.
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And sine t is going to be one over, sorry, s squared minus one.
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Cine t is going to have a little fast transform of 1 over s squared minus 1.
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So it's just s minus 1 over s squared.
01:26
Sorry, it should be a plus 1 at the denominator.
01:31
So cos t has the little transform of s over s squared plus 1...