y = 2074 (25 points). The support consists of a solid Red Brass C83400 copper post surrounded by a 304 stainless steel tube. Before the load is applied, the gap between the two parts is 1 mm. Given the dimensions X10 shown, determine the greatest axial load that can be applied to the rigid cap A without causing any yielding of the materials. Pe = Pst = 7010 = 70 x 10^6 N/m^2. P = 25 mm = 1 mm = 453 N - 4102 Tm^2. 19310^3 x 10 N = 1.03 x 10 N. AVR = 4 Ohm - 51. 0.25 m. 1335.17. 1/2. Ph = 60 mm. 80 mm. -10 mm. e:04_PROB_047. AE. P XX A. 150110-15-40/143103 1 = 315 x 10^-7 - 4.310^-7 P. P = 2SUMN. Par. P = 197 MN. 197 MN (25 mm). 30 mm. 10110 6-A172 mm B250 72-1 = 1335.7193103 PMN. 30 mm = t2.SUMW. 71302. 207103 = Ps276 MN. 1335.17.