Question

y[k] - 0.125y[k - 1] = x[k] + 2x[k - 1] x[k] = 3($\frac{1}{2}$)$^{k-1}$ u[k]

Name: yk 0125yk 1 xk 2xk 1 xk 3frac12k 1 uk 71965
Uploaded: 2023-07-13T04:07:09-08:00
Duration: 4 min 45 s
Channel: Sri K
Description: yk 0125yk 1 xk 2xk 1 xk 3frac12k 1 uk 71965

          y[k] - 0.125y[k - 1] = x[k] + 2x[k - 1]
x[k] = 3($\frac{1}{2}$)$^{k-1}$ u[k]

$yk 0125yk 1 xk 2xk 1 xk 3frac12k 1 uk 71965$

Added by Angela C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

07/13/2023

Step 1

125y[k-1] = x[k] + 2x[k-1]$ $Y(e^{j\Omega}) - 0.125e^{-j\Omega}Y(e^{j\Omega}) = X(e^{j\Omega}) + 2e^{-j\Omega}X(e^{j\Omega})$ $Y(e^{j\Omega})(1 - 0.125e^{-j\Omega}) = X(e^{j\Omega})(1 + 2e^{-j\Omega})$ The frequency response $H(e^{j\Omega})$ is given Show more…

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