00:01
To calculate the ph of the solution, we first need to recognize what is going to be in excess.
00:07
The reaction of hcl with sodium hydroxide is a one -to -one reaction, producing sodium chloride and water.
00:17
So with 50 milliliters of 0 .1 molar sodium hydroxide and only 10 milliliters of .2 molar hcl, we have sodium hydroxide in excess.
00:27
So the excess sodium hydroxide concentration can be calculated.
00:32
By taking the moles of sodium hydroxide, we start with initially, which is going to be the volume of sodium hydroxide in liters.
00:41
50 milliliters is 0 .05000 liters.
00:46
If we multiply that volume by the concentration, 0 .100 moles sodium hydroxide per liter, this will give us the moles sodium hydroxide we start with.
00:58
If we then multiply that by the volume of hcl added, which is 10 mill liters or 0 .01 liters, multiplied by its concentration of 0 .2 0 .0 moles per liter...