You apply a potential difference of 4.50 V between the ends of a wire that is 2.50 m in length a

Name: You apply a potential difference of 4.50 V between the ends of a wire that is 2.50 m in length and 0.654 mm in radius. The resulting current through the wire is 17.6 A . What is the resistivity of the wire?
Uploaded: 2022-07-08T21:25:24-08:00
Duration: 2 min 34 s
Channel: Adi S
Description: You apply a potential difference of 4.50 V between the ends of a wire that is 2.50 m in length and 0.654 mm in radius. The resulting current through the wire is 17.6 A . What is the resistivity of the wire?

Step 1: Calculate the resistance of the wire using the formula ( R = frac{V}{I} ), where ( V

Question

You apply a potential difference of 4.50 $\mathrm{V}$ between the ends of a wire that is 2.50 $\mathrm{m}$ in length and 0.654 $\mathrm{mm}$ in radius. The resulting current through the wire is 17.6 $\mathrm{A}$ . What is the resistivity of the wire?

          You apply a potential difference of 4.50 $\mathrm{V}$ between the ends of a wire that is 2.50 $\mathrm{m}$ in length and 0.654 $\mathrm{mm}$ in radius. The resulting current through the wire is 17.6 $\mathrm{A}$ . What is the resistivity of the wire?

Added by Brandon C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

07/08/2022

Step 1

50 \, V \) and $ I = 17.6 \, A $. Show more…

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You apply a potential difference of 4.50 $\mathrm{V}$ between the ends of a wire that is 2.50 $\mathrm{m}$ in length and 0.654 $\mathrm{mm}$ in radius. The resulting current through the wire is 17.6 $\mathrm{A}$ . What is the resistivity of the wire?