00:01
Hi, in this question we are given with the initial temperature of the stew is 2008 degree fahrenheit and we have the room temperature as 758 degree fahrenheit and we have the serving temperature.
00:15
So, to cool for a serving temperature of so, t s will be 1008 degree fahrenheit.
00:22
So, we have to find the time at which the beef reduces to this serving temperature of 1008 degree fahrenheit and we are given with the cooling rate r is equal to 0 .054.
00:35
Now, we have the formula for finding the serving temperature which is t s is equal to t i minus t r into e power minus r t plus t r on substituting the values we have this is 1008 degree fahrenheit which is equal to 2000 2008 degree fahrenheit minus 758 into e power minus 0 .054 into t plus 758.
01:06
So, this is equal to 1008 which is equal to so, this is 1250 e power minus 0 .054 into t plus 758.
01:17
So, we have so, this goes to this side.
01:20
So, we can have 250 divided by 1250 into is equal to e power minus 0 .04 t...