00:01
Hello students, in this question we are given a vehicle of speed.
00:05
So v is given as 40 miles per hour and we need to convert this into meter per second.
00:16
So one mile per hour is is equal to you can convert this by multiplying with 0 .44704.
00:25
So that is equal to 17 .8816 meter per second.
00:30
Now let's calculate the frequency.
00:34
So here the wavelength is given lambda is given as 10 .3 meter.
00:39
So frequency is equal to v by lambda.
00:42
So that is equal to 17 .8816 divided by 10 .3.
00:49
So that is equal to 1 .737 hertz.
00:55
So that is the frequency.
00:58
Now the magnitude and phase we can calculate.
01:01
Right.
01:02
So the magnitude the equation of motion in the frequency domain we can write down the equation of motion as m omega square plus i omega c plus k times y of omega is equal to c of omega plus k of omega times x of omega.
01:33
So here m omega is the frequency 2 pi nu.
01:39
So omega is equal to 2 pi nu 2 pi f.
01:44
So y of omega is the frequency response term of the system and c of omega is the frequency response of the dashboard.
01:53
K of omega is the frequency response of the spring and x of omega is the frequency response of the road profile.
02:00
So we can compare this equation and we get m omega square plus i omega c plus k must be equal to c omega square plus k.
02:12
So we can simplify this and you can write down m omega square plus i omega c is equal to c omega square.
02:20
Right.
02:21
The constants can be cancelled each other.
02:23
So let's substitute the values of omega in here.
02:27
So you get m.
02:29
So omega is equal to 2 pi nu.
02:33
So omega is equal to 2 pi times f which is 1 .737...