Question

You are given pure samples of ethane, C2H6(g), and toluene, C7H8(l). What prediction would you make concerning their standard molar entropies at 298 K? Group of answer choices S°ethane ≈ S°toluene S°ethane ≈ (S°toluene) ÷ 3 Since toluene is much more complex than ethane, but ethane is in the gas phase while toluene is a liquid, none of the above predictions can be confidently made without further information or calculations. S°ethane > S°toluene S°ethane < S°toluene

          You are given pure samples of ethane, C2H6(g), and toluene, C7H8(l). What prediction would you make concerning their standard molar entropies at 298 K?
Group of answer choices
S°ethane ≈ S°toluene
S°ethane ≈ (S°toluene) ÷ 3
Since toluene is much more complex than ethane, but ethane is in the gas phase while toluene is a liquid, none of the above predictions can be confidently made without further information or calculations.
S°ethane > S°toluene
S°ethane < S°toluene

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Added by Stephanie R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

06/28/2024

Step 1

Standard molar entropy is a measure of the disorder or randomness of a substance at standard conditions (298 K and 1 atm). Generally, larger and more complex molecules have higher entropies due to more possible microstates. Show more…

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You are given pure samples of ethane, C2H6(g), and toluene, C7H8(l). What prediction would you make concerning their standard molar entropies at 298 K? Group of answer choices S°ethane ≈ S°toluene S°ethane ≈ (S°toluene) ÷ 3 Since toluene is much more complex than ethane, but ethane is in the gas phase while toluene is a liquid, none of the above predictions can be confidently made without further information or calculations. S°ethane > S°toluene S°ethane < S°toluene

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