00:01
So, here in this question we are considering a resistance is given that is 50 ohm source which is turned with the frequency that is equal to 100 megahertz attached to a 50 ohm spectrum with a 20 feet value.
00:12
So, basically we need to find out the total lows in the cable.
00:18
So, total lows in the cable from here is given as t of l that become equals to 4 .5 db per 100 feet which is multiplied by the 200 feet.
00:28
So, from here we get the value of t l that is total lows that from here is equals to 9 db.
00:34
Now we have to find out the voltage across 100 ohm resistor or load when it is directly to the attached from here.
00:45
So, here we can say that a 400 ohm load this is equals to 56 .5 of db, d of bv plus 9 of db.
00:56
So, this value from here voltage across 100 load will be equals to 65 .5 of dbv.
01:04
Now we have to find out the reading of the meter.
01:07
So, here we are considering that is d of bm is equals to d of bv minus of 20 which is multiplied by the log of 10 of z plus 10 multiplied by the log of 10 multiplied by the log of 10 of 1000...