You are required to compose a 2M X 8 memory by using only 256K X 8 memory chips. a) How many address lines are needed for the entire memory? b) How many address lines are common to all memory chips? c) How many 256K X 8 memory chips do you need? d) What size decoder is needed?
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Step 1
- The required memory size is 2M x 8 bits. - 2M (megabytes) = 2 x 1024 x 1024 bytes = 2,097,152 bytes. - Since each byte consists of 8 bits, the total memory size is 2,097,152 bytes x 8 bits/byte = 16,777,216 bits. Show more…
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