You are testing the null hypothesis that there is no linear relationship between two variables, X and Y. From your sample of n = 18, you determine that b1 = 4.9 and Sb1 = 1.4. a. What is the value of t_STAT? b. At the ? = 0.05 level of significance, what are the critical values? c. Based on your answers to (a) and (b), what statistical decision should you make? d. Construct a 95% confidence interval estimate of the population slope, ?1. A. H0: ?1 ? 0 H1: ?1 > 0 B. H0: ?1 = 0 H1: ?1 ? 0 C. H0: ?1 ? 0 H1: ?1 = 0 D. H0: ?1 ? 0 H1: ?1 < 0 t_STAT = ______ (Round to two decimal places as needed.) b. The lower critical value is ______. The upper critical value is ______. (Round to four decimal places as needed.) c. What statistical decision should you make? A. Since t_STAT is greater than the upper critical value, do not reject the null hypothesis. B. Since t_STAT is greater than the upper critical value, reject the null hypothesis. C. Since t_STAT is between the two critical values, reject the null hypothesis. D. Since t_STAT is between the two critical values, do not reject the null hypothesis. d. The 95% confidence interval estimate of the population slope is ____ ? ?1 ? ____. (Round to two decimal places as needed.)
Added by Juan Francisco D.
Close
Step 1
9 and Sp1 = 1.4, we have: tSTAT = 4.9 / 1.4 = 3.50 Show moreā¦
Show all steps
Your feedback will help us improve your experience
Cheng Zhang and 83 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
You are testing the null hypothesis that there is no linear relationship between two variables, X and Y. From your sample of n = 12, you determine that r = 0.6. a. What is the value of tSTAT? b. At the Ī± = 0.05 level of significance, what are the critical values? c. Based on your answers to (a) and (b), what statistical decision should you make? a. What are the hypotheses to test? A. H0: Ļ ā¤ 0 H1: Ļ > 0 B. H0: Ļ ā„ 0 H1: Ļ < 0 C. H0: Ļ ā 0 H1: Ļ = 0 D. H0: Ļ = 0 H1: Ļ ā 0 tSTAT = (Round to four decimal places as needed.) b. The lower critical value is . (Round to four decimal places as needed.) The upper critical value is . (Round to four decimal places as needed.) c. What statistical decision should you make? A. Since tSTAT is greater than the upper critical value, do not reject H0. B. Since tSTAT is greater than the upper critical value, reject H0. C. Since tSTAT is between the critical values, do not reject H0. D. Since tSTAT is between the critical values, reject H0.
Ivan K.
You are testing the null hypothesis that there is no linear relationship between two variables, X and Y. From your sample of n=11, you determine that r=0.55. a. What is the value of tSTAT? b. At the Ī±=0.05 level of significance, what are the critical values? c. Based on your answers to (a) and (b), what statistical decision should you make? a. What are the hypotheses to test? A. H0: Ļ=0 H1: Ļā 0 B. H0: Ļā 0 H1: Ļ=0 C. H0: Ļā„0 H1: Ļ<0 D. H0: Ļā¤0 H1: Ļ>0 tSTAT = (Round to four decimal places as needed). b. The lower critical value is (Round to four decimal places as needed). The upper critical value is (Round to four decimal places as needed). c. What statistical decision should you make? A. Since tSTAT is greater than the upper critical value, do not reject H0. B. Since tSTAT is greater than the upper critical value, reject H0. C. Since tSTAT is between the critical values, reject H0. D. Since tSTAT is between the critical values, do not reject H0.
Adi S.
If the null hypothesis is rejected in a one-way ANOVA test of three or more means, then a ScheffƩ Test can be performed to find which means have a significant difference. In a ScheffƩ Test, the means are compared two at a time. For instance, with three means you would have the following comparisons: $\bar{x}_{1}$ versus $\bar{x}_{2}, \bar{x}_{1}$ versus $\bar{x}_{3},$ and $\bar{x}_{2}$ versus $\bar{x}_{3} .$ For each comparison, calculate $$\frac{\left(\bar{x}_{a}-\bar{x}_{b}\right)^{2}}{\frac{S S_{W}}{\Sigma\left(n_{i}-1\right)}\left(\frac{1}{n_{a}}+\frac{1}{n_{b}}\right)}$$ where $\bar{x}_{a}$ and $\bar{x}_{b}$ are the means being compared and $n_{a}$ and $n_{b}$ are the corresponding sample sizes. Calculate the critical value by multiplying the critical value of the one-way ANOVA test by $k-1 .$ Then compare the value that is calculated using the formula above with the critical value. The means have a significant difference when the value calculated using the formula above is greater than the critical value. Refer to the data in Exercise $8 .$ At $\alpha=0.01,$ perform a ScheffƩ Test to determine which means have a significant difference.
Chi-Square Tests and the F-Distribution
Analysis of Variance
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD