You can retry this question below The phyical fitness of an athlete is often measured by how much exypen the athlete takes in (which is recorded in milititers per klogram, mi/kg). The mean maximum oxygen uptake for ebite athletes has been recorded in milititers per kilogram, ming). The mean maximum oxygen uptake for evive atheteb has been Find the probability that an etite athlete has a maximum arygen vptake of at least \( 81 \mathrm{ml} / \mathrm{kg} \). 0.0068 Find the probability that an elite athlete has a maximum oxyen uptake of at most \( 47.1 \mathrm{~m} / \mathrm{kg} \). 0.0228 Check Anower Question 2 \( 1.5 / 3 \mathrm{pts} \) 96.98 Details
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This information is usually given in the form of a mean (average) and a standard deviation. Second, we need to convert the values of 81 ml/kg and 47.1 ml/kg into z-scores. The z-score is a measure of how many standard deviations an element is from the mean. Show more…
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The physical fitness of an athlete is often measured by how much oxygen the athlete takes in (which is recorded in milliliters per kilogram, ml/kg). The mean maximum oxygen uptake for elite athletes has been found to be 75 with a standard deviation of 5.3. Assume that the distribution is approximately normal. (a) What is the probability that an elite athlete has a maximum oxygen uptake of at least 65 ml/kg? Answer: (b) What is the probability that an elite athlete has a maximum oxygen uptake of 70 ml/kg or lower? Answer: (c) Consider someone with a maximum oxygen uptake of 22 ml/kg. Is it likely that this person is an elite athlete? Write "YES" or "NO." Answer: (d) What maximum oxygen uptake would someone need to exceed to be in the top 20% of elite athletes? Answer: ml/kg Round your areas to four decimal places, and your X value to two decimal places.
Gaurav K.
The physical fitness of athletes is measured by ${ }^{4} V_{\mathrm{O}_{2}}$ max," which is the maximum volume of oxygen consumed by an individual during incremental exercise (for example, on a treadmill). An average male has a $V_{\mathrm{O}_{2}}$ max of $45 \mathrm{~mL} \mathrm{O}_{2} / \mathrm{kg}$ body mass $/ \mathrm{min}$, but a world-class male athlete can have a $V_{\mathrm{O}_{2}}$ max reading of $88.0 \mathrm{~mL} \mathrm{O}_{2} / \mathrm{kg}$ body mass/min. (a) Calculate the volume of oxygen, in mL, consumed in $1 \mathrm{hr}$ by an average man who weighs $85 \mathrm{~kg}$ and has a $V_{\mathrm{O}_{2}}$ max reading of $47.5 \mathrm{~mL}$ $\mathrm{O}_{2} / \mathrm{kg}$ body mass $/ \mathrm{min} .(\mathbf{b})$ If this man lost $10 \mathrm{~kg},$ exercised, and increased his $V_{\mathrm{O}_{2}}$ max to $65.0 \mathrm{~mL} \mathrm{O}_{2} / \mathrm{kg}$ body mass $/ \mathrm{min}$, how many mL of oxygen would he consume in $1 \mathrm{hr} ?$
The physical fitness of athletes is measured by " $V_{\mathrm{O}_{2}}$ max," which is the maximum volume of oxygen consumed by an individual during incremental exercise (for example, on a treadmill). An average male has a $V_{\mathrm{O}_{2}}$ max of $45 \mathrm{~mL} \mathrm{O}_{2} / \mathrm{kg}$ body mass $/ \mathrm{min}$, but a world-class male athlete can have a $V_{\mathrm{O}_{2}}$ max reading of $88.0 \mathrm{~mL} \mathrm{O}_{2} / \mathrm{kg}$ body mass $/ \mathrm{min.}$ (a) Calculate the volume of oxygen, in mL, consumed in 1 hr by an average man who weighs 185 lbs and has a $V_{\mathrm{O}_{2}}$ max reading of 47.5 $\mathrm{mL} \mathrm{O}_{2} / \mathrm{kg}$ body mass $/ \mathrm{min}$ (b) If this man lost $20 \mathrm{lb}$, exercised, and increased his $V_{\mathrm{O}_{2}}$ max to $65.0 \mathrm{~mL} \mathrm{O}_{2} / \mathrm{kg}$ body mass $/ \mathrm{min}$, how many mL of oxygen would he consume in $1 \mathrm{hr}$ ?
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