Question

You charge an initially uncharged 72.5 mF capacitor through a 42.9 $\Omega$ resistor by means of a 9.00 V battery having negligible internal resistance. Determine the time constant $\tau$ of the circuit. $\tau$ = s What is the charge $Q(t)$ on the capacitor $t = 1.55\tau$ after the circuit is closed? $Q(1.55\tau)$ = C What is the charge $Q_0$ after a long amount of time has passed? $Q_0$ = C

Name: you charge an initially uncharged 725 mf capacitor through a 429 omega resistor by means of a 900 v battery having negligible internal resistance determine the time constant tau of the circu 14703
Uploaded: 2023-10-17T12:05:41-08:00
Duration: 59 s
Channel: Adi S
Description: you charge an initially uncharged 725 mf capacitor through a 429 omega resistor by means of a 900 v battery having negligible internal resistance determine the time constant tau of the circu 14703

          You charge an initially uncharged 72.5 mF capacitor through a 42.9 $\Omega$ resistor by means of a 9.00 V battery having negligible
internal resistance.

Determine the time constant $\tau$ of the circuit.

$\tau$ = s

What is the charge $Q(t)$ on the capacitor $t = 1.55\tau$ after the
circuit is closed?

$Q(1.55\tau)$ = C

What is the charge $Q_0$ after a long amount of time
has passed?

$Q_0$ = C

you charge an initially uncharged 725 mf capacitor through a 429 omega resistor by means of a 900 v battery having negligible internal resistance determine the time constant tau of the circu 14703

Added by Katrina G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

10/17/2023

Step 1

In this case, $R = 42.9 \, \Omega$ and $C = 72.5 \, mF = 72.5 \times 10^{-3} \, F$. Therefore, $\tau = (42.9 \, \Omega)(72.5 \times 10^{-3} \, F) = 3.10975 \, s$. Rounding to three significant figures, we get $\tau = 3.11 \, s$. Show more…

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You charge an initially uncharged 72.5 mF capacitor through a 42.9 $\Omega$ resistor by means of a 9.00 V battery having negligible internal resistance. Determine the time constant $\tau$ of the circuit. $\tau$ = s What is the charge $Q(t)$ on the capacitor $t = 1.55\tau$ after the circuit is closed? $Q(1.55\tau)$ = C What is the charge $Q_0$ after a long amount of time has passed? $Q_0$ = C