00:01
Here we will apply the ideal gas equation according to each pv is equal to n r t.
00:09
Now in this equation p is representing the pressure of the gas, then v is representing the volume of the gas, n is representing the numbers of mole, r is representing the gas constant, and t is representing the temperature.
00:41
So in the first question, the value of the pressure p is given, which is 0 .101 atmosphere.
00:55
The volume is given, which is 2 .50 litre.
01:01
And the temperature is also given, which is 20.
01:05
Degrees celsius converting into kelvin we will get 22 plus 273 so it will be in kelvin from this first we will find the value of n multiply by r because is remain constant for the gas so here we can write this from the pv is equal to nrt the n nr, so pv is equal to n r t, the value of p is 0 .101, v is 2 .5, nr, the temperature is 22 plus 273 kelvin.
01:59
So here we will get the value of nr is equal to 8 .61 multiplied by 10 this to 4 .4.
02:10
Atmosphere liter per kelvin.
02:16
Now we have to find in the equation b in the equation b the value of pressure p is given which is 0 .139 atmosphere and the volume v is given which is 2 .0 2 .0 later we have to find the temperature value for this and the value of nr we already find.
02:47
So from this, pv is equal to nrt.
02:52
We can write this...