00:01
Hello student, so the question is to describe the formation of the buffer solution from acetate ion and acetic acid.
00:09
So here first we need to find the ratio of the acetate concentration is to the acetic concentration.
00:15
So we will be using the henderson hesselbalch equation which is ph is equal to the pka plus the log value of the acetate ion which is a negative divided by the acetic acid which is ha.
00:36
So here this is the concentration of acetic acid and this is the concentration of acetate ion.
00:41
So let us plug in the value in this formula.
00:44
So here we have been given the ph which is 4 .00 and pka is given as 4 .76.
00:52
So and it is plus the log value of a negative which is the conjugate base of the acetic acid and the divide by the concentration of acetic acid.
01:03
So by using this we will get the log of a negative divide by the concentration of ha which is equal to minus of 0 .76.
01:17
So by removing this log value from here we will get the concentration of a negative divide by the concentration of ha is equal to 10 raised to the power minus 0 .76.
01:32
So by further calculating it we will get the concentration ratios of the acetate ion divide by the concentration of acetic acid and here it is equal to so by calculating it is equal to 0 .174...