Question

You have a job in a company that produces party supplies. You are designing helium-filled balloons to be sold as gifts. To save money on production costs, part of this design is to choose from an available selection the least massive token necessary to be tied to the lower end of the string hanging from the balloon in order to keep the balloon from rising off a table, hospital food tray, bedroom dresser, etc. In this way, the token remains stationary on the flat surface and the balloon is buoyed above the token at a fixed height, with the string straight. You are working on a balloon whose envelope is very thin and has a mass of $0.150 \mathrm{~kg}$. The envelope is filled to a volume of $0.2300 \mathrm{~m}^{3}$ with helium at atmospheric pressure. The string has a mass of $0.0700 \mathrm{~kg}$. Among the selection of tokens are those with masses $10.0 \mathrm{~g}, 20.0 \mathrm{~g}, 30.0 \mathrm{~g}$ $40.0 \mathrm{~g},$ and $50.0 \mathrm{~g} .$ Chose the appropriate token for the balloon you are working on.

          You have a job in a company that produces party supplies. You are designing helium-filled balloons to be sold as gifts. To save money on production costs, part of this design is to choose from an available selection the least massive token
necessary to be tied to the lower end of the string hanging from the balloon in order to keep the balloon from rising off a table, hospital food tray, bedroom dresser, etc. In this way, the token remains stationary on the flat surface and the balloon is buoyed above the token at a fixed height, with the string straight. You are working on a balloon whose envelope is very thin and has a mass of $0.150 \mathrm{~kg}$. The envelope is filled to a volume of $0.2300 \mathrm{~m}^{3}$ with helium at atmospheric pressure. The string has a mass of $0.0700 \mathrm{~kg}$. Among the selection of tokens are those with masses $10.0 \mathrm{~g}, 20.0 \mathrm{~g}, 30.0 \mathrm{~g}$ $40.0 \mathrm{~g},$ and $50.0 \mathrm{~g} .$ Chose the appropriate token for the balloon you are working on.

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Added by Joanna D.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

09/30/2022

Step 1

Given: - Mass of envelope = 0.150 kg - Volume of helium = 0.2300 m^3 - Density of helium = 0.179 kg/m^3 - Mass of string = 0.0700 kg Total weight = Weight due to mass + Weight of envelope and string + Weight of helium Total weight = (m + 0.0700)g + (0.150 + Show more…

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You have a job in a company that produces party supplies. You are designing helium-filled balloons to be sold as gifts. To save money on production costs, part of this design is to choose from an available selection the least massive token necessary to be tied to the lower end of the string hanging from the balloon in order to keep the balloon from rising off a table, hospital food tray, bedroom dresser, etc. In this way, the token remains stationary on the flat surface and the balloon is buoyed above the token at a fixed height, with the string straight. You are working on a balloon whose envelope is very thin and has a mass of $0.150 \mathrm{~kg}$. The envelope is filled to a volume of $0.2300 \mathrm{~m}^{3}$ with helium at atmospheric pressure. The string has a mass of $0.0700 \mathrm{~kg}$. Among the selection of tokens are those with masses $10.0 \mathrm{~g}, 20.0 \mathrm{~g}, 30.0 \mathrm{~g}$ $40.0 \mathrm{~g},$ and $50.0 \mathrm{~g} .$ Chose the appropriate token for the balloon you are working on.

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Transcript

00:01 The density of helium is equal to 0 .179 kg per meter cube and the density of air is equal to 1 .225 kilogram per meter cube.

00:19 So this is the balloon.

00:23 Here a mass is hanged from the balloon.

00:28 So let the mass which is hanging from the balloon.

00:28 So let the mass which is hanging from the balloon.

00:31 B m here we already know that the balloon contains helium gas so weight due to the helium will be acting downwards also here there is a mass attached to it so definitely the weight of this mass also will be acting downwards here given that this is the string this string has a mass of 0 .07 kilogram.

01:02 Also this is known as the envelope.

01:05 Here the envelope is very thin and the mass of the envelope is equal to 0 .15 kilogram.

01:13 So here we must use the formula here the total weight is equal to the buoyant force because the balloon is flowing through the air so definitely air is a fluid it will be producing a buoyant.

01:30 Falls on the balloon.

01:31 Here total weight means first one the weight due to this mass, that is mg, the mass into acceleration due to gravity g.

01:40 This is the first weight plus here there is a string as well as envelope.

01:47 So mass of the string plus mass of the envelope into acceleration due to gravity.

01:55 This is the total weight of the balloon plus we know that there is helium gas.

02:02 Present in it so mass is equal to density into volume so using this formula the mass of helium gas will be equal to the density of helium gas into its volume so here density of helium gas is 0 .179 into the volume is given which is 0 .23 so this is the mass of the helium gas into the acceleration due to gravity g this is the total weight.

02:38 The total weight is equal to the buoy force.

02:40 Bowen force means the force or the weight due to the air.

02:46 So here again, here mass of the air will be equal to density of the air into its volume...

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