00:06
Stock solution and it is 16 .0 molar ammonia.
00:21
Find mills of stock to prepare 1 ,500 milliliters of 0 .2000 molar in h3.
00:45
That'll be x times 16 .0 molar equal 15 .00 molar n h3.
00:48
That'll be x times 16 .0 molar 100 milliliters times 0 .2 .00 molar.
01:07
And even though 1500 only has two sig -figs, i'm gonna assume a volumetric, otherwise i'd have to assume two significant figures.
01:23
Six, and this will be 1500 times point two divided by 16.
01:29
And this x equals 18 .75 milliliters.
01:36
And i would report that as 18 .8 milliliters.
01:41
This is assuming a volumetric.
01:46
So make a note on this one.
01:47
I assumed 1 ,500, well, i don't know, maybe i should report it to two sig -figs...