00:01
We are told that we want to prepare a buffer and we have 250 ml of acetic acid at 0 .480 molar.
00:13
We have 0 .327 molar koh.
00:17
We want to prepare a buffer of 4 .680 molar.
00:21
Okay, so let's begin.
00:25
Quite a few things i got to take care of here.
00:29
I've got my ka for acetic acid.
00:35
I looked up it's 1 .76 times 10 to the minus 5 and if i need it my pka will be 4 .75.
00:47
10 to the minus 4 .680 equals an h3o plus concentration of 2 .089 times 10 to the minus 5th molar.
01:14
Okay, in case i need any of that.
01:17
Now let's go ahead and write down our dissociation.
01:24
Acetic acid will dissociate into our acetate ion and our h plus ion.
01:38
So our ka will be equal to and my ka is 1 .76 times 10 to the minus 5.
01:59
So i can rearrange this and i get my h plus concentration equals my ka which is 1 .76 times 10 to the minus 5 and i'll have my acid over my base and my h plus concentration we just said was 2 .089 times 10 to the minus 5th...