Question

You launch a projectile at an initial speed of 39.8 m/s from the ground. After 3.10 seconds of flight, the projectile lands on the ground. At what angle above the horizontal was the projectile launched? 16.9 degrees 22.5 degrees 33.8 degrees 12.5 degrees

Name: you launch a projectile at an initial speed of 398 ms from the ground after 310 seconds of flight the projectile lands on the ground at what angle above the horizontal was the projectile lau 06056
Uploaded: 2021-12-22T19:48:42-08:00
Duration: 34 s
Channel: Penny Riley
Description: you launch a projectile at an initial speed of 398 ms from the ground after 310 seconds of flight the projectile lands on the ground at what angle above the horizontal was the projectile lau 06056

          You launch a projectile at an initial speed of 39.8 m/s from the
ground. After 3.10 seconds of flight, the projectile lands on the
ground. At what angle above the horizontal was the projectile
launched?
16.9 degrees
22.5 degrees
33.8 degrees
12.5 degrees

Added by Concepci-N P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Penny Riley

12/22/2021

Step 1

The horizontal distance traveled by the projectile can be found using the formula: distance = speed * time distance = 39.8 m/s * 3.10 s distance = 123.38 m Show more…

Show all steps

Thanks for your feedback!

You launch a projectile at an initial speed of 39.8 m/s from the ground. After 3.10 seconds of flight, the projectile lands on the ground. At what angle above the horizontal was the projectile launched? 16.9 degrees 22.5 degrees 33.8 degrees 12.5 degrees