You manage "Goldilocks Porriage". Volunteers were recruited to help determine the ideal porridge temperature. Here (data in blue) are their individual responses for what fahrenheit temperature was "just right". Report the sample stats, and use the t-distribution to find a 95% confidence interval on the population mean. Report all values to the nearest .01 degree. B "just right" temperature (F) 139 (a) sample size (c) sample standard deviation 142 (b) sample mean 140 sample size =12. Standard Deviation=2.42 To find the stadrad deviation I used the excel functiona STDEV.s(B4: B15) 138 136 Sample Mean= 138.64 I used the excel function AVERAGE(B4:B15) (d) margin of error 140 137 (e) confidence interval lower end estimate 136 143 (f) confidence interval upper end estimate 138 136
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Based on a random sample of 100 employees at a large firm, a 95% confidence interval is calculated for the mean age of all of the firm's employees. The interval is (34.5 years, 47.2 years). a. What was the sample mean? (Hint: Where does the point estimate fall within a confidence interval ?) b. Determine the margin of error. 6. It has long been reported that normal human body temperature follows a normal distribution with a mean of 98.6 degrees Fahrenheit. But is the mean really 98.6Ā°F? A group of medical researchers measured the body temperature of a random sample of 18 healthy individuals. After the researchers made their measurements, they entered the data into a statistical software package and ran the appropriate statistical test. The output generated from this test is printed below. Based on this output, what should they conclude and why? T-Test of the Mean Test of mu = 98.60 vs mu not = 98.60 Variable N Mean StDev SE Mean T P TEMP 18 98.2167 0.68363 0.16113 -2.39 0.029
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