Question

You raise a wrecking ball (mass of the ball m) to its maximum height (h) from the ground and then release it to hit a structure you want to demolish. The speed of that ball right before it touches the structure is v. Choose the correct statements and choose all that apply. At the max height, the ball has a potential energy = mgh. Where g is the acceleration due to gravity. Right before the ball touches the structure, the ball has kinetic energy = ½ m v². The velocity of that ball right before it touches the structure: v = ?(2 K. E / m) Where K.E is the kinetic energy. At the max height, the ball has kinetic and potential energy. At the max height, the ball has kinetic energy only. None of the other answers is correct.

          You raise a wrecking ball (mass of the ball m) to its maximum height (h) from the ground and then release it to hit a structure you want to demolish. The speed of that ball right before it touches the structure is v. Choose the correct statements and choose all that apply.

At the max height, the ball has a potential energy = mgh. Where g is the acceleration due to gravity.
Right before the ball touches the structure, the ball has kinetic energy = ½ m v².
The velocity of that ball right before it touches the structure:
v = ?(2 K. E / m)
Where K.E is the kinetic energy.
At the max height, the ball has kinetic and potential energy.
At the max height, the ball has kinetic energy only.
None of the other answers is correct.

Show more…

You raise a wrecking ball (mass of the ball m) to its maximum height (h) from the ground and then release it to hit a structure you want to demolish. The speed of that ball right before it touches the structure is v. Choose the correct statements and choose all that apply.

At the max height, the ball has a potential energy = mgh. Where g is the acceleration due to gravity.
Right before the ball touches the structure, the ball has kinetic energy = ½ m v².
The velocity of that ball right before it touches the structure:
v = ?(2 K. E / m)
Where K.E is the kinetic energy.
At the max height, the ball has kinetic and potential energy.
At the max height, the ball has kinetic energy only.
None of the other answers is correct.

Added by Debra S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adrian Olano

06/24/2022

Step 1

**Step 2:** Right before the ball touches the structure, the ball has kinetic energy 1/2mv^2. **Step 3:** The velocity of the ball right before it touches the structure is v, where KE is the kinetic energy. **Step 4:** At the max height, the ball has both Show more…

Show all steps

lock

Thanks for your feedback!

You raise a wrecking ball (mass of the ball m) to its maximum height (h) from the ground and then release it to hit a structure you want to demolish. The speed of that ball right before it touches the structure is v. Choose the correct statements and choose all that apply: At the max height, the ball has potential energy mgh, where g is the acceleration due to gravity. Right before the ball touches the structure, the ball has kinetic energy 1/2mv^2. The velocity of that ball right before it touches the structure is v, where KE is the kinetic energy. At the max height, the ball has both kinetic and potential energy. At the max height, the ball has kinetic energy only. None of the other answers is correct.

Play audio

Feedback

Powered by NumerAI

Adrian Olano and 56 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

00:01 So let's draw this out real quick.

00:02 We have a wrecking ball.

00:05 Imagine that being a crane is about to be dropped on some building, right? at height h.

00:15 So we have to find out what is true from these four.

00:22 First, we have at max height, the ball has potential energy mgh, where g is acceleration to the gravity.

00:29 Well, the wrecking ball does have a mass, and there is, in fact, acceleration to the energy.

00:33 The gravity acting upon it.

00:35 So the potential energy will indeed be m .g .h.

00:40 So that one is correct.

00:43 2.

00:43 Right before the ball touches the structure right here, not sure why i drew a square, but right here, right, the ball will have a kinetic energy of 1 .5 mv squared.

00:57 Kinetic energy is, in fact, given by 1 .5 mv squared.

01:03 So that is also correct.

01:07 The next one, the ball will have a velocity of 2ke over m squared.

01:22 Well, let's look at this equation again, this one right here.

01:26 Let's try to isolate that v.

01:29 K .e.

01:30 Is equal to one half mv squared.

01:34 Go ahead and move over that one half.

01:36 2k .e is equal to mv squared, divide by m...

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later