00:01
In this problem we have been given that there is a weighing scale and that contains a spring which gets compressed by a distance of 0 .8 millimeter provided that when we stand and let's say our weight is 690 newtons.
00:24
So here the force applied will be 690 newton because it applies in the downward direction.
00:31
So in that case we can definitely say that whatever force is applied that gets developed in the spring as the spring force.
00:41
And because of that only it is able to stop.
00:44
So we get the spring force as k times x according to hook's law.
00:50
So k times x that will be equal to 690.
00:56
And from here we'll put the value of x in meters of course to get the spring constant in newton's per meter.
01:03
That will be 690 divided by 0 .8 into 10 raise to minus 3 newton per meter.
01:10
So when we divide here 690 with 0 .8, we're going to get here as 862 .5 into 10 raise to 3 newtons per meter.
01:24
So that's the spring constant and now it has stated that in the next situation if we jump at a height of 1 .7, meters and then come down.
01:37
So in that case the jump is made from a height of 1 .7 meters from the point of the top of the scale.
01:47
So in this case the total energy contained at this point p from where the jump is made that is equal to m g into the height.
01:56
That's 1 .7.
01:57
And this total energy should be converted into the spring potential energy and that will give us the reading of of the scale.
02:07
So spring potential energy, that's equal to half kx square...