00:01
Hi, so to solve for this we have to write first the balance equation for this reaction.
00:07
We have copper reacting with nitric acid that's hno3.
00:14
Then this will form copper nitrate, nitrogen monoxide, and h2o.
00:23
So to balance this, we need to write 3 here, 2, 4, and then we have to write 8, and then 3 here.
00:32
Now this is the balance equation for this reaction.
00:35
And if we are to solve for the percent yield of the reaction, remember percent yield is equivalent to the actual yield over the theoretical yield of the reaction.
00:45
So the actual yield is given in the problem, and theoretical yield is calculated using stoichiometry.
00:53
So that means we have to solve first for the theoretical yield mass of copper nitrate.
00:58
If we have 2 .25 using the mass of copper, convert to moles by dividing the molar mass of copper, that's 63 .55 grams...