You throw a ball off an 12 m high cliff at an angle of 45° and speed of 30 m/s. How far will the ball go before hitting the ground? a) 133.05 m b) 97.11 m c) 102.57 m d) 121.18 m
Added by Julia R.
Step 1
Substitute the values: \(V_{x} = 30 \cdot \cos(45^\circ) = 30 \cdot \frac{\sqrt{2}}{2} = 15\sqrt{2} \approx 21.21 \, \text{m/s}\). Show more…
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