00:01
For this question, we weigh out 0 .2360 grams of sodium carbonate and carry out a titration with 32 .84 milliliters of 0 .1017 molar hcl.
00:13
The reaction requires 2 moles of hcl for every 1 mole of sodium carbonate, according to this balanced chemical reaction.
00:21
If we start with sodium carbonate in solution and we add hcl, sodium carbonate is a base and will likely be at a ph above 9, where the solution will look pink.
00:34
After adding the hcl, it should drop below ph9 because we have an acidic environment due to the carbon dioxide coming from carbonic acid and it should be colorless.
00:47
These being the two forms of phenothelene, pink in a basic environment and colorless below ph9.
00:58
To calculate the molar mass of sodium carbonate we'll take, we need to know the mass of the compound and we need to know the moles of the compound.
01:07
The mass of the compound is provided.
01:09
We'll divide that by the moles of the compound.
01:12
The moles can be determined from the titration data.
01:20
We'll start with the 32 .84 milliliters of hcl, which is 0 .03284 liters.
01:26
Multiply that by the concentration of 0 .1017 moles per liter to get moles of hcl, which is 0 .0384 liters.
01:33
We then recognize 2 moles hcl react with 1 mole sodium carbonate...