you were asked to make 11000 10 3 dilution of a reagent and you have 10 ml of a dilution that is

Step 1: To make a 1/1000 (10^-3) dilution of a reagent with 10 ml of a 1/100 (10^-2) dilution, w

You were asked to make 11000 10 3 dilution of a reagent and...

You were asked to make a 1/1000 (10^-3) dilution of a reagent, and you have 10 ml of a dilution that is already at 1/100 (10^-2). You want to end up with a total volume of 10 ml. a) What volume of water (diluent) will you need to add to the next tube, and b) What volume of liquid would be taken from the first dilution? If you added one more dilution to the series, by taking 0.1 ml of the dilution to a total volume of 10 ml. a) What would your final dilution of the original sample be? b) How much diluent would you have to add to the last dilution tube? If you were asked to make only 1 ml total volume of the final dilution, how much of the third dilution preparation would you take to dilute it to 1 ml with the same dilution factor?

Transcript

00:01 Hello students welcome here in this question they are asking we have to make one thousand molar concentration of a solution dilution of a reagent and you have 10ml of 10 power minus 2 dilution reagent so here we have to make up 10m.

00:27 Of this solution 10 power minus 3 dilution solution.

00:31 So how much volume of this one should be taken? we have to calculate.

00:35 So we know that c1 v1 is equal to c2 v2.

00:39 So here we have to take how much water and how much reagent we have to take.

00:46 So c1 is 10 .5 minus 2 and v1 we have to calculate and c2 is 10 ml and this one is 10 power minus 3 so then it is equal to um v1 is equal to uh 10 power um um so here it is equal to this is 10 power minus 2 10 power minus 2 gets cancelled so 10 power minus 2 will be and here also 10 power minus 2 so this one is equal to 1m we have to take so to make so to make to make 10 power minus 3 dilution solution.

01:29 Dilution.

01:33 We had to take 1 ml of a 10 power minus 2 dilution reagent.

01:48 And we have to make this one to 10 ml.

01:51 So that's why.

01:52 And add it 9m.

01:57 9m.

01:58 Of water to make 10 power minus 3.

02:05 M dilution reagent 10 ml okay so this is a first question and another thing is if you have only um is here uh what volume of water will you need to add the to the next tube they are asking so 9ml we have already said here 9ml is required and the b question is uh what volume uh what volume of liquid be taken from the first solution one so what how much of solution is required one m .m.

02:47 Is required so one ml and for this one nine ml is correct and the next question is if you add one more dilution to the series by taking 0 .1m.

03:01 Of the solution dilution then how much 10 m l, we had to calculate the concentration here.

03:12 So this one is c1 and this, sorry, this one is c1 and this one is v1 and this one is c2 we have to calculate.

03:22 So c1 is v1 is equal to c2 v2.

03:26 So from this 0 .1m multiplied by 10 power minus 3 is equal to 10 ml.

03:33 So then we will get the c2 is equal to c2 is equal to 10.

03:39 Minus 5 is a c2 concentration here.

03:43 And another question we have here, how much diluent here? the dilution of the last tube is 10 power minus 5.

03:54 So we can write this one 10 power 10000, so 5 zeros.

03:58 And the next question, how much diluent would you have to add to the last dilution tube? so for the last dilution, 0 .1 ml is taken.

04:11 So we have to make up this to 10m...

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