Question

Your answer is incorrect. An object is dropped from an altitude of one Earth radius above Earth's surface. If M is the mass of Earth and R is its radius, the sp the object just before it hits Earth, neglecting air resistance, is given by: $\sqrt{GM/R}$ $\sqrt{GM/2R^2}$ $\sqrt{GM/R^2}$ $\sqrt{2GM/R}$ $\sqrt{GM/2R}$

Name: your answer is incorrect an object is dropped from an altitude of one earth radius above earths surface if m is the mass of earth and r is its radius the sp the object just before it hits ea 99785
Uploaded: 2021-09-25T09:27:21-08:00
Duration: 1 min 1 s
Channel: Narayan Hari
Description: your answer is incorrect an object is dropped from an altitude of one earth radius above earths surface if m is the mass of earth and r is its radius the sp the object just before it hits ea 99785

          Your answer is incorrect.
An object is dropped from an altitude of one Earth radius above Earth's surface. If M is the mass of Earth and R is its radius, the sp
the object just before it hits Earth, neglecting air resistance, is given by:
$\sqrt{GM/R}$
$\sqrt{GM/2R^2}$
$\sqrt{GM/R^2}$
$\sqrt{2GM/R}$
$\sqrt{GM/2R}$

your answer is incorrect an object is dropped from an altitude of one earth radius above earths surface if m is the mass of earth and r is its radius the sp the object just before it hits ea 99785

Added by Jose W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Narayan Hari

09/25/2021

Step 1

The object is dropped from height equal to one Earth radius above the surface, so initial distance from Earth's center r_i = R + R = 2R. Final distance r_f = R. Initial kinetic energy K_i = 0. Gravitational potential energy is U = -GMm/r. Show more…

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Your answer is incorrect. An object is dropped from an altitude of one Earth radius above Earth's surface. If M is the mass of Earth and R is its radius, the sp the object just before it hits Earth, neglecting air resistance, is given by: $\sqrt{GM/R}$ $\sqrt{GM/2R^2}$ $\sqrt{GM/R^2}$ $\sqrt{2GM/R}$ $\sqrt{GM/2R}$