Question

Your answer is partially correct. In the figure the parallel-plate capacitor of plate area 4.60 \times 10^{-2} m^2 is filled with two dielectric slabs, each with thickness 1.40 mm. One slab has dielectric constant 3.50, and the other, 4.20. How much charge does the 1.30 V battery store on the capacitor?

          Your answer is partially correct.
In the figure the parallel-plate capacitor of plate area 4.60 \times 10^{-2} m^2 is filled with two dielectric slabs, each with thickness 1.40 mm.
One slab has dielectric constant 3.50, and the other, 4.20. How much charge does the 1.30 V battery store on the capacitor?

Your answer is partially correct.
In the figure the parallel-plate capacitor of plate area 4.60 ×10^-2 m^2 is filled with two dielectric slabs, each with thickness 1.40 mm.
One slab has dielectric constant 3.50, and the other, 4.20. How much charge does the 1.30 V battery store on the capacitor?

Added by Jacqueline O.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Deepak Jangra

Step 1

The capacitance of a parallel-plate capacitor is given by the formula: C = (ε₀ * εᵣ * A) / d where C is the capacitance, ε₀ is the permittivity of free space (8.85 x 10^-12 F/m), εᵣ is the relative permittivity (dielectric constant) of the material between the Show more…

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Your answer is partially correct. In the figure, the parallel-plate capacitor of plate area 4.60 Ã— 10^-2 m^2 is filled with two dielectric slabs, each with thickness 1.40 mm. One slab has a dielectric constant of 3.50, and the other has a dielectric constant of 4.20. How much charge does the 1.30 V battery store on the capacitor? Number 2.1 Ã— 10^8 Units